x^=2-7x-12+(x+6)=

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Solution for x^=2-7x-12+(x+6)= equation: 



x^=2-7x-12+(x+6)=

We move all terms to the left:

x^-(2-7x-12+(x+6))=0

We add all the numbers together, and all the variables

x-(2-7x-12+(x+6))=0



We calculate terms in parentheses: -(2-7x-12+(x+6)), so:

2-7x-12+(x+6)

determiningTheFunctionDomain
-7x+(x+6)+2-12

We add all the numbers together, and all the variables

-7x+(x+6)-10

We get rid of parentheses

-7x+x+6-10

We add all the numbers together, and all the variables

-6x-4

Back to the equation:

-(-6x-4)



We get rid of parentheses

x+6x+4=0

We add all the numbers together, and all the variables

7x+4=0

We move all terms containing x to the left, all other terms to the right

7x=-4

x=-4/7

x=-4/7

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